Windows 路径中包含空格的 Python `os`

Source: Dev.to

处理文件路径中的空格

当文件路径包含空格时，需要确保 Python 正确解释该字符串。你可以：

• 使用原始字符串（r"..."）来避免转义反斜杠。
• 手动转义每个反斜杠（\\）。

使用原始字符串

import os

# Correct: Use 'r' before the string to create a raw string
path_with_spaces = r"F:\python\New folder (2)"

if os.path.isdir(path_with_spaces):
    print(f"'{path_with_spaces}' is a directory.")
else:
    print(f"'{path_with_spaces}' is NOT a directory or does not exist.")

使用转义的反斜杠

import os

# Alternative: Escape the backslashes
path_with_spaces_escaped = "F:\\python\\New folder (2)"

if os.path.isdir(path_with_spaces_escaped):
    print(f"'{path_with_spaces_escaped}' is a directory.")
else:
    print(f"'{path_with_spaces_escaped}' is NOT a directory or does not exist.")