Clone Graph: Coding Problem Solution Explained
Source: Dev.to
The “Clone Graph” problem asks you to create a deep copy of a connected graph.
Each node in the graph contains a value and a list of its neighbors. The cloned graph must contain entirely new nodes, but it must preserve the exact structure of the original graph, including all connections and cycles. In other words, every node‑and‑edge relationship in the original graph must be mirrored in the clone, without reusing any original objects.
This problem is not about copying values in isolation; it is about duplicating relationships. The real challenge lies in correctly recreating the graph’s topology, especially when cycles and shared neighbors are involved.
Why naive copying fails
- A naive approach might try to recursively copy each node and its neighbors. This quickly breaks down when the graph contains cycles. Without careful handling, the algorithm can fall into infinite recursion, repeatedly trying to clone the same nodes.
- Another common mistake is duplicating nodes multiple times. If two nodes in the original graph both reference the same neighbor, the clone must also reference a single cloned version of that neighbor, not two separate copies. Failing to preserve this one‑to‑one correspondence leads to an incorrect graph structure.
Check out the Island Perimeter coding‑problem solution for an example of handling edge cases.
Recognizing the need for a mapping
The key insight is that cloning a graph is fundamentally about maintaining a mapping between original nodes and their cloned counterparts. Every time you clone a node, you must remember that clone so you can reuse it later if the original node is encountered again.
The mapping serves two purposes:
- Prevents infinite loops when the graph contains cycles.
- Ensures structural consistency by guaranteeing that each original node corresponds to exactly one cloned node.
Graph traversal as the foundation
To clone a graph you must visit every node and inspect its neighbors. This naturally leads to graph‑traversal techniques such as depth‑first search (DFS) or breadth‑first search (BFS). Either strategy works, as long as you systematically explore all reachable nodes.
During traversal, the mapping is checked first:
- If the current node has already been cloned, simply return the existing clone.
- If not, create a new clone, store it in the mapping, and then proceed to clone its neighbors.
See also the solutions for Sum of Left Leaves and
Bitwise AND of Numbers Range.
Why depth‑first and breadth‑first both work
- DFS tends to be conceptually simple because it mirrors the recursive definition of a graph: clone a node, then recursively clone its neighbors.
- BFS processes nodes level by level using a queue.
Both approaches are correct because the mapping guarantees that each node is cloned exactly once, regardless of traversal order. The choice between them is mostly a matter of style and comfort.
Handling cycles safely
Cycles are what make this problem interesting. In a cyclic graph you can revisit the same node through different paths. Without the mapping, this would cause infinite recursion or repeated cloning.
With the mapping in place, cycles become harmless. When a previously visited node is encountered again, the algorithm simply retrieves its clone from the mapping and links to it, preserving the cycle structure perfectly in the cloned graph.
Building neighbor relationships correctly
Cloning nodes alone is not enough; you must also rebuild each node’s neighbor list. This is done by iterating through the original node’s neighbors and attaching the corresponding cloned neighbors to the cloned node.
Because neighbors may or may not have been cloned yet, this step relies on recursive calls (DFS) or queued traversal steps (BFS). The mapping ensures that neighbor references always point to the correct cloned objects.
Why this approach guarantees correctness
- Every original node is visited and cloned exactly once.
- Every original edge is recreated between the corresponding cloned nodes.
Since the mapping enforces a one‑to‑one correspondence and traversal ensures full coverage, the cloned graph is structurally identical to the original, with no shared references between them.
Time and space complexity considerations
- Time: (O(N + E)) – linear in the number of nodes (N) and edges (E), because each node and each edge is processed once.
- Space: (O(N)) – for the mapping and for the recursion stack (DFS) or queue (BFS).
This efficiency is optimal for graph cloning; you cannot clone fewer nodes or edges than exist in the original graph.
Why this problem is common in interviews
Clone Graph is a classic interview problem because it tests whether candidates truly understand:
- Graph traversal techniques.
- The difference between shallow and deep copies.
- Proper handling of cycles.
It also checks the ability to manage auxiliary data structures (e.g., a hash map) to preserve relationships during traversal.
What this problem teaches beyond graph cloning
Beyond the specific task, the problem illustrates a broader lesson about duplicating interconnected data structures. Whenever objects reference each other, cloning requires tracking identity, not just values.
If you can clearly explain why a mapping is essential, how traversal explores the graph safely, and how cycles are handled without special cases, you demonstrate strong algorithmic reasoning. That depth of understanding makes “Clone Graph” an e
Excellent exercise in graph traversal, memory management, and deep‑copy semantics.
If you want more coding problems explained, check out: